Question

there were 288, 336, and 192 member of three different companies in a conference find the minimum number of rows required if the number of members to be seated in each row must be from the same company

Answer 1

Answer:

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Answer 2

Solution :-

Number of rows will be minimum when maximum number of members seated in each row .

given that, same number of members to be seated in each row must be from the same company .

so, maximum number of members seated in each rows be HCF of 288, 336 and 192 .

prime factors of 288, 336 and 192 are :-

→ 288 = 2 * 2 * 2 * 2 * 2 * 3 * 3

→ 336 = 2 * 2 * 2 * 2 * 3 * 7

→ 192 = 2 * 2 * 2 * 2 * 2 * 2 * 3

then,

→ HCF = 2 * 2 * 2 * 2 * 3 = 48

therefore, in each rows 48 members can be seated .

hence,

→ Minimum number of rows = Total members of all 3 companies / 48 = (288 + 336 + 192)/48 = 816/48 = 17 rows (Ans.)

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