Math, asked by dinacampus08, 1 year ago

there were 40 members in a certain hotel. if 10 members are more admitted the expenses of the mess was increase by Rs. 50 per month while the average expenditures per head diminished by Rs. 3. the Original monthly expenses are.

Answers

Answered by rimjhim4116
0
plz mark brainliest amswer
Attachments:

dinacampus08: The answer will be Rs. 620 , 800, 700 or 850
Answered by pulakmath007
2

The original monthly expenses = Rs. 800

Given :

  • There were 40 members in a certain hotel.

  • If 10 members are more admitted the expenses of the mess was increase by Rs. 50 per month while the average expenditures per head diminished by Rs. 3

To find :

The original monthly expenses

Solution :

Step 1 of 2 :

Form the equation to find original monthly expenses

Let the original monthly expenses = Rs. x

Since there were 40 members in a certain hotel

∴ Average expenditures per head = Rs. x/40

If 10 members are more admitted then total number of members = 40 + 10 = 50

When total number of members is 50 expenses of the mess was increase by Rs. 50 per month

So new total expenses will be = Rs. (x + 50)

∴ New average expenditures per head

= Rs. (x + 50)/50

By the given condition

\displaystyle \sf   \frac{x}{40}  -  \frac{x + 50}{50}  = 3

Step 2 of 2 :

Calculate original monthly expenses

\displaystyle \sf   \frac{x}{40}  -  \frac{x + 50}{50}  = 3

\displaystyle \sf{ \implies }  \frac{5x - 4(x + 50)}{200}  = 3

\displaystyle \sf{ \implies }  \frac{5x - 4x  - 200}{200}  = 3

\displaystyle \sf{ \implies }  x  - 200 = 3 \times 200

\displaystyle \sf{ \implies }  x - 200= 600

\displaystyle \sf{ \implies }  x  = 600 + 200

\displaystyle \sf{ \implies }  x  = 800

Hence original monthly expenses = Rs. 800

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If the sum of twelve marks is 510, what is their average?

https://brainly.in/question/38904597

2. The mean of 5 numbers is 39. If one number is excluded, their mean is 35, find the excluded number

https://brainly.in/question/33419522

#SPJ3

Similar questions