There were 96 coins in a box. 1/3 of the coins were $1 coins, 1/4 of the remaining coins were 50 ¢ coins and the rest were 10 ¢ coins. A. How many 10 ¢ coins were there? B. Find the total value of all the coin in the box
Answers
Answered by
4
Answer:
1 $=96/3= 32 Nos
50 ¢=(96-32)x 1/4 = 16 Nos
10¢= (96-48) = 48 Nos
.Value
$x32= 3200
50¢x16= 800
10¢x48. 480
Total. 4 480 ¢
$44 and ¢80
Similar questions