Math, asked by patelarya, 1 year ago

there where two. friends. what is the probability of getting 1)same birthday (ignoring leap year and 2) different birthday.

Answers

Answered by sivamammu
1
1) 1/365
2) 364/365
if it is correct make it as brainliest

sivamammu: welcome
Answered by shivani12320
1
P(same birthday)= 1/365
P(different birthday) =364/365

Hope it is helpful
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