there where two. friends. what is the probability of getting 1)same birthday (ignoring leap year and 2) different birthday.
Answers
Answered by
1
1) 1/365
2) 364/365
if it is correct make it as brainliest
2) 364/365
if it is correct make it as brainliest
sivamammu:
welcome
Answered by
1
P(same birthday)= 1/365
P(different birthday) =364/365
Hope it is helpful
P(different birthday) =364/365
Hope it is helpful
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Math,
8 months ago
Sociology,
1 year ago
Math,
1 year ago