Question

Therefore,
BC
sin A
AC
So.
2 sin A cos A = 2
which
√ √2
Example 5 : In A OPQ, right-angled at P,
OP = 7 cm and OQ PQ = 1 cm (see Fig. 11.12)
Determine the values of sin Q and cos 0
Solution : In A OPQ, we have
OQP = OP + PO​

Answer 1

Answer:

sin Q = 7/1 and cos O = 7/1