Math, asked by dev9524kumar7, 10 months ago

Therefore
EXAMPLE & Suppose we represent the distance above the ground by a positive inte
and that below the ground by a negative integer, then answer the followin
1 An elevator descends into a mine shaft at the rate of 5 metre per minute. What wil
be its position after one hour?
() Ifit begins to descend from 15 m above the ground, what will be its position after 45
minutes?​

Answers

Answered by Janadeen
2

Above the ground +ve, below the ground level -ve.

Q 1: speed = - 5m/min

Time given 1hour = 60 min.

Then distance = speed × time = -5 × 60

Distance = -300 m.

Q 2: position of lift = + 15 m

Speed = -5m/min.

Time = 45 min.

Distance = speed × time. = -5 × 45 = -225 m.

So the position of lift is +15 - 225 m

= -210 m.

Thank u.

Hope this helps you

Please mark as brainliest if you think it is so.

@spyder

Similar questions