Question

Thermal energy is applied to 2.4 kg of water on a stove. If the specific heat of water is 4.2 kJ/(kg·K) and the water temperature increases by 5.1 K, how much thermal energy was applied to the water?

A. 12,0000 J

B. 14,000 J

C. 51,000 J

D. 102,000 J

Answer 1

Answer:B

Explanation:

Answer 2

The thermal energy is 51000 J.

(C) is correct option.

Explanation:

Given that,

Mass of water = 2.4 kg

Specific heat = 4.2 kJ/kg.K

Temperature = 5.1 K

We need to calculate the thermal energy

Using formula of thermal energy

$Q=mc\Delta T$

Where, m = mass of water

c = specific heat

$\Delta T$ = change temperature

Put the value into the formula

$Q=2.4\times4.2\times10^{3}\times5.1$

$Q=51408\aproxx 51000\ J$

Hence, The thermal energy is 51000 J.

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Topic : Thermal energy

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