Physics, asked by harshapala5928, 1 year ago

thermally insulated vessels 1 and 2 are filled with air at temperature T1 and t2 volume V1 V2 pressure P1 P2 respectively the value in the two vessels is opened the temperature inside the vessel at equilibrium will be

Answers

Answered by rahman749951
2

P1V1/T1=P2V2/T2...................

Answered by brainlyteacher63
34
<b>No of moles of system remains same

 \dfrac{P_1V_1}{RT_1} + \dfrac{P_2V_2}{RT_2} = \dfrac{P(V_1 + V_2)}{RT}

T \: \: = \: \dfrac{P(V_1 + V_2)T_1T_2}{P_1V_1T_2 + P_2V_2T_1}

According to Boyle's law

P_1V_1 + P_2V_2 = P(V_1 + V_2)

 T \: \: = \: \: \dfrac{(P_1V_1 + P_2V_2)T_1T_2}{(P_1V_1T_2 + P_2V_2T_1)}
Similar questions