Question

*THERMODYNAMICS*

One mole of CO₂ is heated from 273 K to 373 K at constant pressure. The work done in process is?
a)100J
b)200R
c)50R
d)100R




please help me out ​

Answer 1

Answer:

100R id answer

Explanation:

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Answer 2

The work done in the process is d) 100R J

Number of moles of CO₂ is (n) = 1 mole

Initial temperature = 273 K

Final temperature = 373 K

∴ Change in temperature (ΔT) is = (373 - 273) K

                                                      = 100 K

Work done, dW = nRdT

∴ W = nRΔT [R is the universal gas constant]

∴ W = 1 × R × 100 J

⇒ W = 100R J

The work done in the process is 100R J.