therom .. prove that √3 is an irrational number
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this is your answer proof
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Hii buddy..
Answer:
Let us assume the country that root 3 is a rational number such that there exist two integers A and b where root 3 equal to a by b since a divided by b is coprime
Therefore √3= a/b
By squaring on both sides
3= (a/b)²
Which implies 3= a²/b²
Which implies 3b² =a²
Lets a= 3 *c , where c is an integer
a² =9c²
Which implies 3b²= 9c²
b² =3c²
This contradicts assumption that a and b have no common factors because a and b have common factor three so our assumption is wrong that root 3 is rational therefore root 3 is irrational
Hopes it helps
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thesun1:
sorry but upside perfect answer with steps
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