Math, asked by harshitvani2016, 1 year ago

thers are three brother .the sum of ages of two of them at a time are 4.6.8 years find the differance b/t the age of the eldest and find the youngest brother

Answers

Answered by nitthesh7
23

Let the ages of three brothers  be A,B,C

According to question,

A + B = 4

B + C = 6

A + C = 8

From these

A - 3 yr

B - 1 yr

C - 5 yr

Hence difference of eldest brother and younger brother is 5 - 1 = 4 yr


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Answered by Sanskriti141
37
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