thers are three brother .the sum of ages of two of them at a time are 4.6.8 years find the differance b/t the age of the eldest and find the youngest brother
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Let the ages of three brothers be A,B,C
According to question,
A + B = 4
B + C = 6
A + C = 8
From these
A - 3 yr
B - 1 yr
C - 5 yr
Hence difference of eldest brother and younger brother is 5 - 1 = 4 yr
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