Math, asked by Tusharkakde, 3 months ago

These is a cubicol room whose length measus
6 meteosHow many students can accommodo
if each student requires 27 m3 of space​

Answers

Answered by Anonymous
0

Question:-

There is a cubical room whose length measures 6 metres. How many students can accommodate in the room of each student requires 27 m³ of space?

Given:-

  • \sf{Length\: of \:cubical \:room = 6\: metres}
  • \sf{Space\: each \:student \:requires = 27{m}^{3}}

To find:-

  • \sf{Number\: of \:students\: that\: can\: be\: accommodated\: in\: the \:room.}

Solution:-

\sf{Side \:of \:a \:Cubical\: room = 6 m}

We know,

\sf{Volume\:of\:a\:Cube = {(side)}^{3}cubic\:units}

Therefore,

\sf{Volme\:of\:the\:room = {(6)}^{3}\:{m}^{3}}

= \sf{Volume\:of\:the\:room = 216\:{m}^{3}}

\sf{To\:find\:the\:number\:of\:students\:that\:can\:be\:accommodated\:in\:the\:room,\:we\:need\:to\:divide\:the\:volume\:of\:the\:room\:by\:space\:each\:student\:requires.}

Therefore,

\sf{Number\:of\:students = \dfrac{216{m}^{3}}{27{m}^{3}}}

\sf{Number\:of\:students = 9}

\sf{\therefore 9\:students\:can\:accommodated \:in \:the\:cubical\:room\:measuring\:6\:metres.}

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