Question

these times is smallest of three consecutive odd numbers decreased by 7 equal twice the larger what are the number​

Answer 1

Hey mate, Here is your answer ↓

Let the smallest number be x

2nd no. be x+2

3rd bo. be x+4

A/Q,

→ 3x - 7 = 2(x+4)

→ 3x - 7 = 2x + 8

→ 3x - 2x = 8 + 7

→ x = 15.

Hence, The 1st no. is 15

2nd no. is 15 + 2 = 17

3rd no. is 15 + 4 = 19

Hope it helps you (^•^)

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