Math, asked by dina27, 1 year ago

theta+α=π/4 then (tan theta+1)(tanα+1) is equal to

Answers

Answered by abhi178
0
α + Θ = π/4
take both sides , tan
tan( α + Θ) = tanπ/4
tanα + tanΘ = 1 - tanα.tanΘ
tanα + tanΘ + tanα.tanΘ + 1= 2
( tanα + 1)(tanΘ + 1) = 2
Answered by pankaj12je
1
Hey there !!!!!!

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

θ+α = π/4

Applying tan on both sides

tan(θ+α) = tanπ/4

Using tan(A+B) =tanA+tanB/1-tanAtanB

tanθ+tanα/1-tanθtanα = 1


tanθ+tanα  = (1-tanθtanα)

tanθ+tanα +tanθtanα = 1

Adding 1 on both sides


tanθ+tanα +tanθtanα+1 = 1+1

tanθ+tanα +tanθtanα+1=2

tanθ+tanα(1+tanθ)+1=2

(tanθ+1)+tanα(1+tanθ)=2

(tanθ+1)(tanα+1)=2

(tanθ+1)(tanα +1)= 2


~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hope this helped you...........







Similar questions