Question

theta+α=π/4 then (tan theta+1)(tanα+1) is equal to

Answer 1

α + Θ = π/4
take both sides , tan
tan( α + Θ) = tanπ/4
tanα + tanΘ = 1 - tanα.tanΘ
tanα + tanΘ + tanα.tanΘ + 1= 2
( tanα + 1)(tanΘ + 1) = 2

Answer 2

Hey there !!!!!!

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θ+α = π/4

Applying tan on both sides

tan(θ+α) = tanπ/4

Using tan(A+B) =tanA+tanB/1-tanAtanB

tanθ+tanα/1-tanθtanα = 1


tanθ+tanα  = (1-tanθtanα)

tanθ+tanα +tanθtanα = 1

Adding 1 on both sides


tanθ+tanα +tanθtanα+1 = 1+1

tanθ+tanα +tanθtanα+1=2

tanθ+tanα(1+tanθ)+1=2

(tanθ+1)+tanα(1+tanθ)=2

(tanθ+1)(tanα+1)=2

(tanθ+1)(tanα +1)= 2


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Hope this helped you...........