theta=60°,value of 1+tan square theta /2tan square theta
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So, if theta's value is 60°,
(1+tan^2 60°)/(2 tan^2 60°)
= [1+( root 3 )^2] / [ 2* ( root 3 )^2]
= (1+3)/(2*3)
= 4/6
= 2/3 or, 0.66
Hope this helps.
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