Question

Thethe hypotenuse of a right angle triangle is 25 M if one side is 5 metres more then the other side find its area

Answer 1

If ABC is a right angled triangle right angled at B 

then AC = 25 cm ( given ) 

let other side be x 

then one side be 5 + x 

ATQ

25² = x² + (x+5)²

625 = 2x² + 25 + 10x

2x² + 10x -600 = 0 

x² + 5x - 300 = 0 

a = 1 

b = 5 

x = - 300 

D = b² - 4ac 

= 25 - ( 4 x 1 x (-300)

= 25 + 1200 

= 1225 

two roots are -b+√D/2a and -b-√D/2a 

-5 + √1225 /2  and -5 -√1225 / 2 

-5 + 35 /2 and -5 -35/2 

30/2 and -40/2 

15 and -20 

negative value will be neglected as side of triangle cant be negative so 
x= 15 cm 

5 + x = 20 cm 


Area of triangle = 1/2 x b x h 
 
= 1/2 x 15 x 20 

= 150 cm²

Answer 2

area of triangle is
1×base×height/2
=1/2×20×15
=150 centimeter²......
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