Question

They arranged the 36 cm iron wire in the form of a square and connecte
3 cells in series across one of the diagonals of the square. The value of
current in the circuit is:
A. 0.5 A
B. 0.75 A
C. 1 A
D. 1.5 A
:​

Answer 1

Explanation:

They arranged the 36 cm iron wire in the form of a square and connecte 3 cells in series across ... The value of current in the circuit is: A. 0.5 A B. 0.75 A C. 1 A D. 1.5 A : .

Answer 2

The value of current in the circuit is C. 1 A

The length of the wire = 36 cm

If we consider 1Ω resistance per cm of the wire, then the total resistance of the wire will be = 36Ω

It is placed as square.

So, each of the am of the square will have = 36/4 = 9Ω resistance.

Now, the cells are added across the diagonal of the square.

So, the equivalent resistance will be = (9+9)/2 = 9Ω

We know, from Ohm's law, V = IR

where V = Voltage

          I = Current

          R = Resistance

Given, V = (3×3) V [∵ 3 cells of 3 V are added in series]

∴ I = V/R

⇒ I = 9/9 A

⇒ I = 1 A

∴ The value of current in the circuit will be 1 A.