Question

They sum of three numbers constitutive multiplies of 11 is 363. Find tge multiples


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Answer 1

Answer:

The multiples are 110, 121, 132

Step-by-step explanation:

Correct Question:

The sum of three numbers consecutive multiplies of 11 is 363. Find the multiples.

Solution:

Let the 3 consecutive multiples of 11 be:

• 11 (x)
• 11 (x + 1)
• 11 (x + 2)

As observed (x), (x + 1), (x + 2) are consecutive numbers and all are multiplied by 11 to get the multiples of 11.

According to the Question,

   11(x) + 11(x + 1) + 11(x + 2) = 363

⇒ 11x + 11x + 11 + 11x + 22 = 363

⇒ 11x + 11x + 11x + 22 + 11 = 363

⇒ 33x + 33 = 363

⇒ 33x = 363 - 33

⇒ 33x = 330

⇒ x = 330 ÷ 33

⇒ x = 10

Substitute the value of x in the 3 consecutive multiples considered above to find them.

• 11(x) = 11(10) = 110
• 11(x + 1) = 11(10 + 1) = 11(11) = 121
• 11(x + 2) = 11(10 + 2) = 11(12) = 132

∴ The 3 consecutive multiples are 110, 121, 132