Question

they three years ago?
The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their
ages will be 9: 7. Find their present ages.​

Answer 1

Answer:

Therefore,  The Leena’s age is 28 years and Heena’s age is 20 years.

Step-by-step explanation:

The ages of Leena and Heena are in the ratio 7:5.

Thus there ages are, Leena 7x and Heena 5x

Ten years hence, the ratio of their ages will be 9:7.

10 year hence their ages will be

Leena’s age 7x + 10

Heena’s age 5x + 10

The ratio of their ages :

7x + 10 / 5x + 10

= 9 / 7

Cross multiplication :

9 ( 5x + 10 ) = 7 ( 7x + 10 )

45x + 90 = 49x + 70

45x - 49x = 70 - 90

—5x = -20

5x = 20

x = 20/5

x = 4

The rational is 4

.Their respective ages.

Leena’s age 7x = 7 × 4 = 28 years

Heena’s age 5x = 5 × 4 = 20 years

Therefore,  The Leena’s age is 28 years and Heena’s age is 20 years.

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Answer 2

Answer:

Let ages of leena and heena be 7x and 5x

After ten years, their ages = 7x+10 and 5x+10 respectively.

The ratio of their ages ten years hence: 9x and 7x.

So, we will solve by mai ng an equation: i.e.;

7x + 10 + 5x + 10 = 9x + 7x

12x + 20 = 16x

20 = 16x - 12x

20 = 4x

20 / 4 = x

Therefore x = 5

Their present ages are: 7x = 7*5 = 35

5x = 5*5 = 25.

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