Question

thheta =3t square +2 find angular velocity at 3 second in 3 second ​

Answer 1

$let \: thetha \: = \beta \\ \beta = 3 {t}^{2} + 2 \\ \frac{d \beta }{dx} = \frac{d3 {t}^{2} }{dx} + \frac{d2}{dx} \\ v = 2 \times 3t \: + 0 \\ v = 6t \\ \\ velocity \: at \: t \: = 3sec \: will \: be \\ v = 3 \times 6 \\ v = 18m {s}^{ - 1}$

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