Question

Thickness of a cylinder measured using a screw gauge of
least count 0.01 cm is found to be equal to 0.80 cm. The
percentage error in measurement is
2.5%
1.25%
5%
0.5%​

Answer 1

Answer:

Step-by-step explanation:

Given,

        Thickness (t)= 0.802cm

        Least count= 0.001 cm

now error in measuring t=(0.802±0.001)

So, percentage error=0.001/0.802×100%

                                =0.1246%

                                ≈0.125%

Volume of cylinder V=πr2L

∴ Percentage error in volume

⇒VΔV​×100=r2Δr​×100+lΔl​×100

                          =2(2.00.01​)×100+5.00.1​×100

                          =(1+2)=3 .

Answer 2

option a

Step-by-step explanation:

2.5

all the best