Thickness of the glass slab)/(Thickness of glass slab - Vertical shift) = _____
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Shift due to glass slab =
t[1−
μ
1
]=(6)[1−
3
2
]=(6)[
3
1
]=2 cm
Since radius of curvature =40 cm
Object must be placed on a distance of 42 cm so that due to shift they will be at 40 cm and both coincide.
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