Math, asked by ritikkumar296888, 7 hours ago

Think About a Plan A company logo is a white square inside a red square. The side length of the white square is x+2.The side length of the red square is three times the side length of the white square. What is the area of the red part of the logo? Write your answer in standard form.


- How can drawing a diagram help you solve the problem?


- How can you express the area of the red part of the logo as a difference of areas?

Answers

Answered by swaransingh49957
1

Answer:

$$8 x^{2}+32 x+32$$

I hope it's helpful

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Answered by fidajaleel
0

Answer:

8x^2+32x+32

Step-by-step explanation:

Given:

The side length of the white square = x+2

The side length of the red square = 3(x+2)

Area of square = a×a (a=side)

=> area of white square = (x+2)(x+2)

= (x+2)^2

= x^2+2(x)(2)+2^2

=x^2+4x+4

=> area of red square = 3(x+2) × 3(x+2)

= (3x+6)^2

= (3x)^2+2(3x)(6)+6^2

= 9x^2+36x+36

=> area of the red part of the logo =

area of red square-area of white square

9x^2+36x+36 - x^2+4x+4

= 8x^2+32x+32

HOPE THIS ANSWER WILL HELP YOU!

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