Question

Think and Answer 1. For what value of the unknown, will the length of the boundary of the given fields be 1320 metra 2x metre x metre x metre x metre x matre 4x metre 3x metre (a) ( b)​
please answer it immediately;read the question in the photo above

Answer 1

Answer:

ok done you are in higher classes

Answer 2

Answer:

1. x = 440/pi meters and 2. x = 330/pi meters.

Step-by-step explanation:

1. The given boundaries can be obtained by dividing the field into 4 semi-circles's perimeter of radius of 1 1.5x meter, and 3 0.5x meter. Sum of the perimeters of the semi-circles curved length is equal to given boundary.

curved line perimeter of semi-circle =

$\pi \times r$

where r is the radius

So,

$(\pi \times \frac{3x}{2} ) +( 3 \times \pi \times \frac{1x}{2} ) = 1320 \\ \frac{3\pi \: x}{2} + \frac{3\pi \: x}{2} = 1320 \\ 3\pi \: x = 1320 \\ x = \frac{1320}{3\pi} = \frac{440}{\pi} meters$

2.The given boundaries can be obtained by dividing the field into 4 semi-circles's perimeter of radius of 1 2x meter, 1 x meter, and 2 0.5x meter. Sum of the perimeters of the semi-circles curved length is equal to given boundary.

curved line perimeter of semi-circle =

$\pi \: r$

where r is the radius

So,

$(\pi \times 2x) + (\pi \times x) + (2 \times \pi \frac{x}{2} ) = 1320 \\ 2\pi \: x + \pi \: x + \pi \: x = 1320 \\ 4\pi \: x = 1320 \\ x = \frac{1320}{4\pi} = \frac{330}{\pi} meters$