Think of 2 events each for the following probabilities:
(i) 0
(ii) between 0 and 1/2
(iii) 1/2
(iv) between 1/2 and 1
(v) 1
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Answer:
It is given that P(A)=0.42,P(B)=0.48,P(AandB)=0.16
(i) P(notA)=1−P(A)=1−0.42=0.58
(ii) P(notB)=1−P(B)=1−0.48=0.52
(iii) We know that P(AorB)=P(A)+P(B)−P(AandB)
∴P(AorB)=0.42+0.48−0.16=0.74
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