Math, asked by aniketotari6472, 2 months ago

Think of 5 positive integers that have a mode of 2 and 5, a median of 5 and a mean of 4.

Answers

Answered by gayatripayghan
0

Answer:

mode=4, median=6, mean=7, range=10

Step-by-step explanation:

Let the 5 positive integers be a,b,c,d,e in ascending order.

mode=4 means 4 is one of the number and it comes most frequently [more than once].

median=6 means the middle number [third of the 5 number]

c=6

mean=7 means (a+b+c+d+e)÷5=7

therefore, a+ b+ c +d+ e= 35

range=10 means (e-a)=10

considering the mode 4 appears twice .since c=6 the only way 4 appears twice is if a=b=4

e=10+a=14

d=35-(a+b+c+e)

=35-(4+4+6+14)=7

CHECK:

If the set is 4,4,6,7, 14

mode=4

median =6

mean= 4+4+6+7+14/5 =7

Range=14-4=10

Therefore, the set is 4,4,6,7, 14

thanku!!!!

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