Question

Think of a number . Divide the sum of 8 and the number by 3, the result is more than one quater of the number. Find the number ​

Answer 1

Answer:

The answer is any number greater than (–32)

Step-by-step explanation:

Let the number be x

As per the question —

$\frac{x + 8}{3} > \frac{x}{4}$

Multiplying both sides by 12 —

$4x + 32 > 3x$

So,

$x > ( - 32)$

Hence, x is any number greater than (–32)

Hope this helps you :)

Answer 2

Answer:

a number is 56 greater than the average of its third, quater and one twenth. find the number

Step-by-step explanation:

Let the number be X

Given that 56 greater than the average of its third and 1/12th.

X=56+1/2(3/4x1/12)

X=56+1/2(10x/12)

X=56+5x/12

X=5x/12=56

7x/12=56

X=96

The number =96

Hope it's helpful to all army and blinks