think of a positive number, say x. from the square of this number subtract 3 times of itself. if the result is 10, find x.
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x3 -3=10》x3=10+3=13》x= (13)3=2197
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x=-2 or 5
x^-3x-10=0
product of roots is -10
sumof roots is -3 therefore the roots must be (x-5); (x+2)
then x=5 x=2
x^-3x-10=0
product of roots is -10
sumof roots is -3 therefore the roots must be (x-5); (x+2)
then x=5 x=2
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