Think of any unknown number. Take away 9 from it. Multiply 6 to the result. Add the sum of 4 and y with the result. What is the result.
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We could replace the number 6 in this statement by any other number we like ... In this module we will use the word pronumeral for the letters used in algebra. ... one distinguishes between 'variables' in functions and 'unknown quantities' in ... Multiply the result by 3. Add 15. Subtract 5 times the number you first thought of.
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a) 4+8α=60 let α be the number.
⇒8α=56
⇒α=7
b) let the number be x
Given :- 51×(x)−4=3
5x=7⇒x=35
c) let the number be P
Given :- 43(P)+3=21
43(P)=18⇒P=6×4=24
d) let the number be 'y'
Given 2y−11=15
⇒2y=26
⇒y=13
(e) let the number be 'z'
50−3(z)=8
⇒3(z)=4z⇒′z′=14
(f) let the number that was thought be 'k'
Given :- 5(k+19)=8⇒k+19=40
⇒k=21
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