Think of two numbers.thrice the first number minus the second number is 19 and twice the first number plus five times the second number is -10.Find the product of the two numbers?
Answers
Answer:
- 20.
Step-by-step explanation:
Let those two numbers are a and b. { first number is a }
According to the situation given :
= > thrice of the first number - second number = 19
= > thrice of a - b = 19
= > 3a - b = 19
= > 3a - 19 = b ...( 1 )
Situation 2 :
= > twice of the first number + five times the second number = - 10
= > 2a + 5b = - 10
= > 2a + 5( 3a - 19 ) = - 10 { from ( 1 ) }
= > 2a + 15a - 95 = - 10
= > 17a = 95 - 10
= > a = 85 / 17
= > a = 5
Hence
b = 3( 85 / 17 ) - 19
= ( 255 - 323 ) / 17
= - 68 / 17
= - 4
Required numbers are 5 & - 4.
And their product is - 4 x 5 = - 20.
Answer:
Let the Numbers be x and y.
☯ STATEMENT 1 :
↠ Thrice of 1st No. – 2nd No. = 19
↠ 3x – y = 19
↠ 3x – 19 = y
↠ y = 3x – 19 ⠀⠀— eq. ( I )
☯ STATEMENT 2 :
↠ Twice of 1st No. + 5 × (2nd No.) = – 10
↠ 2x + 5y = – 10
- putting the value of y from eq. ( I )
↠ 2x + 5(3x – 19) = – 10
↠ 2x + 15x – 95 = – 10
↠ 17x = 95 – 10
↠ 17x = 85
- Dividing both term by 17
↠ x = 5
________________
★ Putting value of x in eq. ( I ) :
↠ y = 3x – 19
↠ y = 3(5) – 19
↠ y = 15 – 19
↠ y = – 4
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★ PRODUCT OF NUMBERS :
⇴ x × y
⇴ 5 × – 4
⇴ – 20
∴ Product of Numbers will be – 20.