Question

third equation of motion graphically explain each term used in the expression

Answer 1

Third Equation of Motion. ... The above threeequations can be derived by graphical method. Consider the velocity-time graph of an object moving under uniform acceleration. To derive v = u + at (Velocity - Time relation) In the above figure, 'u' is not equal to zero.

Answer 2

Let the initial velocity of the object = u

Let the object is moving with uniform acceleration, a.

Let object reaches at point B after time, t and its final velocity becomes, v

Draw a line parallel to x-axis DA from point, D from where object starts moving.

Draw another line BA from point B parallel to y-axis which meets at E at y-axis.

Let OE = time, t

Now, from the graph,

BE = AB + AE

⇒ v = DC + OD (Since, AB = DC and AE = OD)

⇒ v = DC + u (Since, OD = u)

⇒ v = DC + u ------------------- (i)

Now, Acceleration (a)  

=change in velocity/timetaken

=>a = v- u/t

=>OC - OD/t = DC/t

By substituting the value of DC from (ii) in (i) we get

v= at +u

v= u +at