Third equation of motion v²=u²+2as prove that
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Graph for derivation
we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]
Hope this helps you ❤❤
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Answer:
For getting the third law of motion equation, we use both of the equations of motion
S = ut + 1/2at2__________(1)
v = u + at _____________ (2)
t = (v – u)/a
Substitute the value of t in equation (1)
S = ut + 1/2at2
S
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2aS = 2u(v − u) + (v − u)2
2aS = 2uv − 2u2 + v2 − 2uv + u2
2aS = v2 − u2
v2 = u2 + 2aS
Explanation:
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