Question

Third excitation energy of Li+2 ions is :
(a) 108.81 eV
(b) 114.75 eV
(c) 51 eV
(d) 48.36 eV
please answer fast​

Answer 1

Answer:

a 108.81 ev

Explanation:

electronic configuration for Li^2+ ion will be 1s^1

Answer 2

Third excitation energy of $Li^{2+}$ ions is 108.81 ev ( Option a is the correct answer)

Given,

$Li^{2+}$

To Find,

Find the third excitation energy of $Li^{2+}$ ions

Solution,

• Excitation in chemistry is the process of adding a specific quantity of energy (excitation energy) to a system, such as an atomic nucleus, an atom, or a molecule, which causes the system to change, often from its ground state of lowest energy to one of higher energy (excited state).

Energy of the electron in the nth orbit

 $E_{n} = \frac{-13.6 * Z^{2} }{n^{2} }$

we have to find the third excitation energy of $Li^{2+}$

for, $Li^{2+}$ , Z= 3

For first orbit, n= 1

$E_{1} = \frac{-13.6 * 3^{2} }{1} ev$

=>$E_{1} = - 122.5 ev</p><p></p><p><strong>Now, for third orbit, n= 3</strong></p><p>[tex]E_{3} = \frac{-13.6 * 3^{2} }{3^{2} } ev$

=> $E_{3} = - 13.6 ev</p><p> </p><p><strong>so, total energy </strong><strong>required </strong><strong>:</strong><strong> </strong></p><p>[tex]∆E= E_{2} - E_{1}$

=> [tex]∆E= -13.6 + 122.5

=> [tex]∆E= 108.81 ev

Hence, Third excitation energy of Li+2 ions is 108.81 ev

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For more information about excitation energy, you can refer to the following questions

Define- excitation energy

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The excitation energy of a hydrogen atom from its ground state to its third excited state is

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