Question

Third term for quadratic equation x2-8x=0

Answer 1

Explanation:

We can rewrite the equation in standard form as:

x2+8x+0=0

Now, we can use the quadratic equation to solve this problem:

The quadratic formula states:

For ax2+bx+c=0, the values of x which are the solutions to the equation are given by:

x=−b±√b2−(4ac)2⋅a

Substituting:

1 for a

8 for b

0 for c gives:

x=−8±√82−(4⋅1⋅0)2⋅1

x=−8±√64−02

x=−8±√642

x=−8−82 and x=−8+82

x=−162 and x=02

x=−8 and x=0

=========================================

A simple way to solve this equation without the quadratic is to factor an x out of each term on the left side of the equation:

x(x+8)=0

Then solve each term on the left for 0:

Solution 1:

x=0

Solution 2:

x+8=0

x+8−8=0−8

x+0=−8

x=−8

Answer link