Third term of an AP is 8 and the 17th term is 51/2. The 23rd term
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3rd term=a+(3-1)d=8
a=8-2d--------------(1)
17th term=a+(17-1)d=51/2
8-2d+16d=51/2
14d=51/2-8
14d=35/2
d=35/2×(1/14)
d=5/4
a=8-2(5/4)
=8-5/2=11/2
23rd term=11/2+(23-1)5/4
=11/2+(22)(5/4)
=11/2+55/2=66/2=33
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