this 8 question I want solution
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a=bq+r
Assume that toot3is rational
root3=p/q
square on both sides
(root3)²=(p/q)²
3 =p²/q²
3q²=p²
3 is a factor of p²
3 is also a factor of p
p=3m
3q²=3m²
3q²=9m²
q² =3m²
3 is a factor of q²
3 is also a factor of q
Hence by our contradiction root3
is irrational
Step-by-step explanation:
2.)a=bq+r
5+3root2=k
3root2 =k-5
root2 =k-5/3
root2 is irrational and k-5/3 is rational so
5+3root2 is irrational
3.)
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