this answer in book is x = 9 cm,y=12 cm , z = 15cm
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Answer:
Solution:
Given
Principal (p) = Rs50000
Rate of interest (r) = 8% p.a
Let the amount at the end of the second year = A
\boxed{Amount = p\times(1+\frac{r}{100})^{n}}
Amount=p×(1+
100
r
)
n
i)
Let the number of times interest paid in 2 years ( n)=2
A = 50000[1+8/100]²
= 50000 × (108/100)²
= 5×108×108
= Rs58320
Therefore,
The amount standing to her
credit at the end of the second
year (A) = Rs58320
ii ) Finding interest for third year:
P = Rs 58320,
R = 8%
T = 1 year
Simple Interest (I) = (PTR)/100
= ( 58320 × 1 × 8 )/100
= Rs 4665.60
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