Question

this bits give options please

1) the equation whose roots are smaller by 1 than those 2x^2-5x+6=0 is
a) 2x^2-9x+13=0
b) 2x^2-x+3=0
c) 2x^2+9x+13=0
d) 2x^2+x+3=0

2) if alpha, bita are the roots of 9x^2+6x+1=0, then the equation with the roots 1/alpha , 1/bita , is
a) 2x^2+3x+18=0
b) x^2+6x-9=0
c) x^2+6x+9=0
d) x^2-6x+9=0

3) the equation whose roots are numerically equal but opposites in sign of the roots of 2x^2-3x-2=0
a) 2x^2+3x-2=0
b) 2x^2+3x+2=0
c) 3x^2-2x-3=0
d) 3x^2+2x+3=0 ​

Answer 1

Answer:

Step-by-step explanation:

1)A

2)C

3)B

Answer 2

Answer:

Option C

Option B

Option A

This is your answer