CBSE BOARD X, asked by harshika79, 9 months ago

this figure angle AOB is 110° then angle PAB is ​

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Answered by atahrv
6

Answer:

∠PAB=55°

Explanation:

As we know that,

∠OAP=∠OBP=90°  (∵TANGENTS TO THE CIRCLE FROM THE SAME                                           POINT ARE PERPENDICULAR TO THE CIRCLE)

FROM THE FIGURE, IT IS CLEAR THAT ∠OAB=∠OBA.

So, IN ΔAOB

LET THE ∠OBA=∠OAB=X

∠AOB+∠OBA+∠OAB=180°

110°+X+X=180°

2X=180°-110°

X=70°/2

X=35°

NOW,

∠OAP=∠PAB+∠OAB

90°=∠PAB+35°

∠PAB=90°-35°

∠PAB=55°

HOPE THIS HELPS YOU...

Answered by vijayagarwalsunita
0

Answer:

Explanation:

yes , answer is 55 degree we know that angle aob = 110 then due to angle sum property remianing two are 35 degre and 35 degree and when we subtract 90 by 5= 90-35 then answer will be 55
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