this figure angle AOB is 110° then angle PAB is
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6
Answer:
∠PAB=55°
Explanation:
As we know that,
∠OAP=∠OBP=90° (∵TANGENTS TO THE CIRCLE FROM THE SAME POINT ARE PERPENDICULAR TO THE CIRCLE)
FROM THE FIGURE, IT IS CLEAR THAT ∠OAB=∠OBA.
So, IN ΔAOB
LET THE ∠OBA=∠OAB=X
∠AOB+∠OBA+∠OAB=180°
110°+X+X=180°
2X=180°-110°
X=70°/2
X=35°
NOW,
∠OAP=∠PAB+∠OAB
90°=∠PAB+35°
∠PAB=90°-35°
∠PAB=55°
HOPE THIS HELPS YOU...
Answered by
0
Answer:
Explanation:
yes , answer is 55 degree we know that angle aob = 110 then due to angle sum property remianing two are 35 degre and 35 degree and when we subtract 90 by 5= 90-35 then answer will be 55
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