Question

This figure is made from a part of a square and a part of a circle.

a. What is the perimeter of this figure, to the nearest unit?

b. What is the area of this figure, to the nearest square unit?

Please answer A, and B.

Answer 1

Answer:

a) Finding the perimeter of the given figure:

Arc length, ED = ∅/

Therefore,

The perimeter of the given figure is,

= AC + CD + ED + EF + AF

= 10 + 5 + 7.85 + 5 + 10

= 37.85 units

rounding off to the nearest unit

↪ 38 units

Thus, the perimeter of the given figure is → 38 units.

b) Finding the area of the given figure:

Area of the sector, HED = ∅/360 × πr²

= 90/360 × 22/7 × (5)²

= 19.64cm²

Area of the square, ABHG = 5² = 25 units²

Area of the square, BCDH = 5² = 25 units²

Area of the square, EFGH = 5² = 25 units²

Therefore,

The area of the given figure is,

= Area(HED) + Area(ABHG) + Area(BCDH) + Area(EFGH)

= 19.64 + 25 + 25 + 25

= 94.64 units²

rounding off to the nearest square unit

↪ 95 units²

Thus, the area of the given figure is → 95 units².