This following table given the frequency distribution of quiz marks obtain by first year student in Stat222
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Marks: 9,6,5,3,8,4,7.
Freqcy:2,8,y,6,4,y-2,6.
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If the mean mark is 5.5
(i) find the value of y,
(ii) calculate the median and mode of the distribution.
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Answer:
y = 9
mode = 5
Step-by-step explanation:
Marks: 9,6,5,3,8,4,7.
Freqcy:2,8,y,6,4,y-2,6.
Total Marks = 9*2 + 6*8 + 5y + 3*6 + 8*4 + 4(y-2) + 7*6
= 18 + 48 + 5y + 18 + 32 + 4y -8 + 42
= 9y + 150
Total Students = 2 + 8 + y + 6 + 4 + y-2 + 6
= 2y + 24
Mean = (9y + 150)/(2y + 24)
=> 5.5 = (9y + 150)/(2y + 24)
=> 11y + 132 = 9y + 150
=> 2y = 18
=> y = 9
Mode = 5 as max 9 students got these marks
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