this function is what onto , many one , one one , into ?
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f( x ) = ln{ √(1+x⁴ ) - x²}
first we check is this function one -one ??
we know , that any function y= f(x) will be one-one only when , dy/dx is strictly increasing or strictly decreasing .
now, differentiate f(x) wrt x
dy/dx = 1/{√(1+ x⁴) - x²} × { 4x³/2√(1+x⁴) -2x }
= 1/{ √( 1+x⁴)-x²} ×2{ x³- x√(1+x⁴)}/√(1+x⁴)
= -2×x/√(1+x⁴ )
= -2x/√(1+x⁴)
we know, exponential function always positive so, √(1+x⁴)> 0
but - ∞ < x < ∞
so, dy/dx is positive as well as negative e.g dy/dx >0 or < 0
so , function is many- one function .
first we check is this function one -one ??
we know , that any function y= f(x) will be one-one only when , dy/dx is strictly increasing or strictly decreasing .
now, differentiate f(x) wrt x
dy/dx = 1/{√(1+ x⁴) - x²} × { 4x³/2√(1+x⁴) -2x }
= 1/{ √( 1+x⁴)-x²} ×2{ x³- x√(1+x⁴)}/√(1+x⁴)
= -2×x/√(1+x⁴ )
= -2x/√(1+x⁴)
we know, exponential function always positive so, √(1+x⁴)> 0
but - ∞ < x < ∞
so, dy/dx is positive as well as negative e.g dy/dx >0 or < 0
so , function is many- one function .
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2
we can see that here ...
range of function = co - domain
so function is onto.
but function not strictly increasing and decreasing so it is many -one.
=) function is many -one onto
______________________________
hope it will help u
range of function = co - domain
so function is onto.
but function not strictly increasing and decreasing so it is many -one.
=) function is many -one onto
______________________________
hope it will help u
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