Question

This is a case study question of maths class 10
can someone plz help​

Answer 1

Answer:

parabola

1

+4,-4

Step-by-step explanation:

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Answer 2

Answer:

1)it has the shape of the parabola

2)it has only one zero

3)x^2-x-12=0

x^2-4x+3x-12

x(x-4)+3(x-4)

(x+3) (x-4)

so the zeroes are -3 and 4

4)sum of zeroes=0

4+ another zero=0

another zero=0-4

=-4

x^2-(4+(-4))x+(4×-4)

x^2-0x+(-16)

so the quadratic polynomial is x^2-16