Math, asked by AnswerBank16, 1 month ago

this is a is multiple correct question

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Answered by ltzBrainlyStarShivam
0

Given that 2x - 3y = 10, xy = 16

∴ (2x - 3y)3 = (10)3

⇒ 8x3 - 27y3 - 3 (2x) (3y) (2x - 3y) = 1000

⇒ 8x3 - 27 y3 -18xy (2x - 3y) = 1000

⇒ 8x3 - 27 y3 - 18 (16) (10) = 1000

⇒ 8x3 - 27 y3 - 2880 = 1000

⇒8x3 - 27 y3 = 1000 + 2880

⇒ 8x3 - 27 y3 =3880

Answered by ltzBrainlyStarShivam
0

Given that 2x - 3y = 10, xy = 16

∴ (2x - 3y)3 = (10)3

⇒ 8x3 - 27y3 - 3 (2x) (3y) (2x - 3y) = 1000

⇒ 8x3 - 27 y3 -18xy (2x - 3y) = 1000

⇒ 8x3 - 27 y3 - 18 (16) (10) = 1000

⇒ 8x3 - 27 y3 - 2880 = 1000

⇒8x3 - 27 y3 = 1000 + 2880

⇒ 8x3 - 27 y3 =3880

Answered by ltzBrainlyStarShivam
1

Given that 2x - 3y = 10, xy = 16

∴ (2x - 3y)3 = (10)3

⇒ 8x3 - 27y3 - 3 (2x) (3y) (2x - 3y) = 1000

⇒ 8x3 - 27 y3 -18xy (2x - 3y) = 1000

⇒ 8x3 - 27 y3 - 18 (16) (10) = 1000

⇒ 8x3 - 27 y3 - 2880 = 1000

⇒8x3 - 27 y3 = 1000 + 2880

⇒ 8x3 - 27 y3 =3880

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