This is a long answer type question plz answer it in that way.
(a) State the principle of working of a potentiometer.
(b) In the following potentiometer circuit AB is a uniform wire of length 1 m and resistance10 2 Ω.
Calculate the potential gradient along the wire and balance length AO (= l).
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i) When a constant current flows through a wire of uniform cross section the fall of potential is directly proportional to the length of wire .
(ii) Total resistance of primary circuit =15 + 10 =25Ω
Current in wire AB,I=2/25=.08A
P.D . across wire =.08 × 10 = 0.8V
Potertial gradient =0.8/100=0.008Vcm−1
Resistance of secondary circuit =1.2+0.3=1.5Ω
Current I = 1.5/1.5=1A
Current in 0.3 Ω resistor = 1A
P.D. across 0.3Ω resistor = 0.3 V
Length AO=0.3V/0.008=37.5cm
Explanation:
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