Physics, asked by HayahMehak00, 11 hours ago

This is a physics question.

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Answered by mahanteshgejji
1

Answer:

Equivalent resistance of the ckt = 3 Ω

Explanation:

R₁ and R₂ are in series.

Equivalent resistance of R₁ and R₂ is

R₁₂ = R₁ + R₂ = 3 + 3 = 6 Ω

R₁₂ and R₃ are in parallel

Equivalent resistance of R₁₂ and R₃ is

Rp = (R₁₂ x R₃) /(R₁₂ + R₃)

= 6 x 3 /9

= 2 Ω

R₄ , Rp and R₅ are in series.

Equivalent resistance of the circuit is

Req = R₄ + Rp + R₅

= 0.5 + 2 + 0.5

= 3 Ω

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