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Answer:
Equivalent resistance of the ckt = 3 Ω
Explanation:
R₁ and R₂ are in series.
Equivalent resistance of R₁ and R₂ is
R₁₂ = R₁ + R₂ = 3 + 3 = 6 Ω
R₁₂ and R₃ are in parallel
Equivalent resistance of R₁₂ and R₃ is
Rp = (R₁₂ x R₃) /(R₁₂ + R₃)
= 6 x 3 /9
= 2 Ω
R₄ , Rp and R₅ are in series.
Equivalent resistance of the circuit is
Req = R₄ + Rp + R₅
= 0.5 + 2 + 0.5
= 3 Ω
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