Question

this is a question of 9th std ratio and proportion lesson

please ans me asap
with a clear format​

Answer 1

It is question for algebraic equations not ratio and proportion

Answer 2

$\rm{\displaystyle[\left(3x-4\right)^3-\left(x+1\right)^3]/[\left(3x-4\right)^3+\left(x+1\right)^3]=61/189}$

$\longrightarrow\rm{\displaystyle[\left(3x-4\right)^3-\left(x+1\right)^3]/(28x^3-105x^2+147x-63)=61/189}$

$\longrightarrow\rm{\displaystyle(26x^3-111x^2+141x-65)/(28x^3-105x^2+147x-63)=61/189}$

$\longrightarrow\rm{\left(26x^3-111x^2+141x-65\right)\cdot \:189=\left(28x^3-105x^2+147x-63\right)\cdot \:61}$

$\longrightarrow\rm{4914x^3-20979x^2+26649x-12285=1708x^3-6405x^2+8967x-3843}$

$\longrightarrow\rm{3206x^3-14574x^2+17682x-8442=0}$

$\longrightarrow\rm{x\approx \:2.99999\dots }\longrightarrow\rm{x\approx \:3 }$