This is a question of chapter Matrices
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Answered by
5
3a+4b= 2....... Eq (1)
a-2b = 4.......... Eq(2)
2a-4b=8(multiply with 2) ..... E.q (2)
On solving eq 1 and 2 we get (elimination method)
a= 2and b = -1
C+d = 5...... Eq (3)
2c-d= -5...... Eq(4)
On solving eq 3 and 4 we get (elimination method)
C=0, d= 5
There for the values of a, b, c, d are 2,-1,0,5 respectively
a-2b = 4.......... Eq(2)
2a-4b=8(multiply with 2) ..... E.q (2)
On solving eq 1 and 2 we get (elimination method)
a= 2and b = -1
C+d = 5...... Eq (3)
2c-d= -5...... Eq(4)
On solving eq 3 and 4 we get (elimination method)
C=0, d= 5
There for the values of a, b, c, d are 2,-1,0,5 respectively
tiwaritejaswi3ox5qsi:
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Answered by
2
heres ur answr ..
a = 2
b = - 1
c = 0
d = 5
thnk.huh
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