Math, asked by santhoshVenugopal, 1 month ago

ретот
This is a required question
Two pipes can fill a tank in 10 hours and 12
hours while a third pipe empties the full
tank in 20 hours. If all the three pipes
operate simultaneously, in how much
time will the tank be filled? *​

Answers

Answered by budhiramsab
1

Net part filled In 1 hour =1/10+1/12-1/20=8/60=2/15. The tank will be full in 15/2 hrs = 7 hrs 30 min.

Answered by nitikamurarka
1

HOPE THE SOLUTION HELPS

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