This is a wall clock. It falls down and breaks into two pieces. The addition of the digits in the smaller piece is 31
And the digits in the bigger piece add upto 30
How exactly did the wall clock break? Remember only 2 pieces.
Answers
Question says that sum of digits in the smaller piece is 31 and in larger piece is 30
so total sum = 30+31=61
Notice that "digit" means "0,1,2,3,4,5,6,7,8,9"
So if you add only digits then sum=61 is not possible in any case
like
[1+2+3+4+5+6+7+8+9+10+11+12]
break numbers into digits
[1+2+3+4+5+6+7+8+9+1+0+1+1+1+2]
=51
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Answer is possible only if we consider to add numbers not the digits.
If we break the clock so that number 12 seprates in 1 and 2. and number 8 gets damaged fully then we get:
Sum of numbers in small piece = 1+11+10+9=31
Sum of numbers in bigger piece = 7+6+5+4+3+2+1+2=30
So the final answer is that clock has to break number 12 so that 1 and 2 gets separated and number 8 gets damaged completely.
The question clearly tells that the clock breaks into two pieces.
- The sum of all the numbers in the first piece is 31.
- The sum of all the numbers in the other piece is 30.
Explanation:
The clock breaks between 12 and 8 separating the numbers 1 and 2 vertically from 12 and divides 8 into 0 and 0 horizontally.
If that's the case,
The numbers on the first piece are 0,9,10,11 and 1.
Their sum is 31.
The numbers on the second piece are 2,1,2,3,4,5,6,7.
Their sum is 30.
Hence, the clock breaks vertically separating 1 and 2 from 12 and horizontally separating 8 into 0 and 0.
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